1/(x^2-x-2)-x/(x^2-5x+6)

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Solution for 1/(x^2-x-2)-x/(x^2-5x+6) equation: 


D( x )

x^2-(5*x)+6 = 0

x^2-x-2 = 0

x^2-(5*x)+6 = 0

x^2-(5*x)+6 = 0

x^2-5*x+6 = 0

x^2-5*x+6 = 0

DELTA = (-5)^2-(1*4*6)

DELTA = 1

DELTA > 0

x = (1^(1/2)+5)/(1*2) or x = (5-1^(1/2))/(1*2)

x = 3 or x = 2

x^2-x-2 = 0

x^2-x-2 = 0

x^2-x-2 = 0

DELTA = (-1)^2-(-2*1*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)+1)/(1*2) or x = (1-9^(1/2))/(1*2)

x = 2 or x = -1

x in (-oo:-1) U (-1:2) U (2:3) U (3:+oo)

1/(x^2-x-2)-(x/(x^2-(5*x)+6)) = 0

1/(x^2-x-2)-(x/(x^2-5*x+6)) = 0

1/(x^2-x-2)+(-1*x)/(x^2-5*x+6) = 0

x^2-x-2 = 0

x^2-x-2 = 0

x^2-x-2 = 0

DELTA = (-1)^2-(-2*1*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)+1)/(1*2) or x = (1-9^(1/2))/(1*2)

x = 2 or x = -1

(x+1)*(x-2) = 0

x^2-5*x+6 = 0

x^2-5*x+6 = 0

x^2-5*x+6 = 0

DELTA = (-5)^2-(1*4*6)

DELTA = 1

DELTA > 0

x = (1^(1/2)+5)/(1*2) or x = (5-1^(1/2))/(1*2)

x = 3 or x = 2

(x-2)*(x-3) = 0

1/((x+1)*(x-2))+(-1*x)/((x-2)*(x-3)) = 0

1/((x+1)*(x-2))+(-1*x*(x+1))/((x+1)*(x-2)) = 0

1-1*x*(x+1) = 0

1-x^2-x = 0

1-x^2-x = 0

1-x^2-x = 0

DELTA = (-1)^2-(-1*1*4)

DELTA = 5

DELTA > 0

x = (5^(1/2)+1)/(-1*2) or x = (1-5^(1/2))/(-1*2)

x = (5^(1/2)+1)/(-2) or x = (1-5^(1/2))/(-2)

(x-((5^(1/2)+1)/(-2)))*(x-((1-5^(1/2))/(-2))) = 0

((x-((5^(1/2)+1)/(-2)))*(x-((1-5^(1/2))/(-2))))/((x+1)*(x-2)) = 0

((x-((5^(1/2)+1)/(-2)))*(x-((1-5^(1/2))/(-2))))/((x+1)*(x-2)) = 0 // * (x+1)*(x-2)

(x-((5^(1/2)+1)/(-2)))*(x-((1-5^(1/2))/(-2))) = 0

( x-((1-5^(1/2))/(-2)) )

x-((1-5^(1/2))/(-2)) = 0 // + (1-5^(1/2))/(-2)

x = (1-5^(1/2))/(-2)

( x-((5^(1/2)+1)/(-2)) )

x-((5^(1/2)+1)/(-2)) = 0 // + (5^(1/2)+1)/(-2)

x = (5^(1/2)+1)/(-2)

x in { (1-5^(1/2))/(-2), (5^(1/2)+1)/(-2) }

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